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Do you think Pyrobyte is a Communist?

Is Pyrobyte a Communist?

  • YES

    Votes: 4 66.7%

  • NO

    Votes: 2 33.3%
  • Total voters
    6
Easy......

Let's look at the decimal of [sup]2[/sup]/[sub]3[/sub]

The decimal would be 0.6666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666...... etc
But if you simply wrote 0.6666666666666666666 the last 6 would have to be a 7, because you'd be writing it to 19 places, and because the next 6>=5 then the 6 rounds up to 7.

In otherwords, 2/3 in decimal places from 10 to 1 is:
0.6666666667
0.666666667
0.66666667
0.6666667
0.666667
0.66667
0.6667
0.667
0.67
0.7

However, with 0.99999999999999..... etc, it would be:
1.000000000
1.00000000
1.0000000
1.000000
1.00000
1.0000
1.000
1.00
1.0

Why?

If you round 0.647238 to 5 decimal places, the 8/1000000 rounds up to 10/1000000 which is equal to 1/100000 which adds on to the 3/100000 to make 4/100000 and therefore, it's 0.64724 to 5 decimal places.

Again, to 2 decimal places, the 7/1000 rounds up to 10/1000 which is 1/100 which adds on to the 4/100 to make 5/100 so the decimal to 2 places is 0.65

But how does it work for 0.999999........ well I just told you... but I'll say it again.
Let's just write it as 0.999999
If you continue to write it, the next number would be 9, but we're rounding it to 6 places, so that 9/10000000 rounds up to 10/10000000 which is 1/1000000 which adds on to the 9/1000000 which makes that 10/1000000 which is 1/100000 which adds on to the 9/100000 to make 10/100000 which is 1/10000 which adds onto the 9/10000 which makes that 10/10000 which is 1/1000 which adds onto the 9/1000 which makes that 10/1000, which is 1/100, plus the 9/100 = 10/100, which is 1/10, added onto the 9/10 makes 10/10 which is 1.
 
Last edited by a moderator:
TheUltimateKoopa said:
Easy......

Let's look at the decimal of [sup]2[/sup]/[sub]3[/sub]

The decimal would be 0.6666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666...... etc
But if you simply wrote 0.6666666666666666666 the last 6 would have to be a 7, because you'd be writing it to 19 places, and because the next 6>=5 then the 6 rounds up to 7.

In otherwords, 2/3 in decimal places from 10 to 1 is:
0.6666666667
0.666666667
0.66666667
0.6666667
0.666667
0.66667
0.6667
0.667
0.67
0.7

However, with 0.99999999999999..... etc, it would be:
1.000000000
1.00000000
1.0000000
1.000000
1.00000
1.0000
1.000
1.00
1.0

Why?

If you round 0.647238 to 5 decimal places, the 8/1000000 rounds up to 10/1000000 which is equal to 1/100000 which adds on to the 3/100000 to make 4/100000 and therefore, it's 0.64724 to 5 decimal places.

Again, to 2 decimal places, the 7/1000 rounds up to 10/1000 which is 1/100 which adds on to the 4/100 to make 5/100 so the decimal to 2 places is 0.65

But how does it work for 0.999999........ well I just told you... but I'll say it again.
Let's just write it as 0.999999
If you continue to write it, the next number would be 9, but we're rounding it to 6 places, so that 9/10000000 rounds up to 10/10000000 which is 1/1000000 which adds on to the 9/1000000 which makes that 10/1000000 which is 1/100000 which adds on to the 9/100000 to make 10/100000 which is 1/10000 which adds onto the 9/10000 which makes that 10/10000 which is 1/1000 which adds onto the 9/1000 which makes that 10/1000, which is 1/100, plus the 9/100 = 10/100, which is 1/10, added onto the 9/10 makes 10/10 which is 1.
Click to expand...
But under that logic, wouldn't something like 0.25 = 0.256? Or 0.5 = 0.51?
Why are we rounding? How can we round infinite decimals?
What the hell are these mathematicians thinking?
 
They're distracting you while they build rockets out of cheese so they can escape to a new planet while we do math.
 
Last edited by a moderator:
Dev said:
TheUltimateKoopa said:
Easy......

Let's look at the decimal of [sup]2[/sup]/[sub]3[/sub]

The decimal would be 0.6666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666...... etc
But if you simply wrote 0.6666666666666666666 the last 6 would have to be a 7, because you'd be writing it to 19 places, and because the next 6>=5 then the 6 rounds up to 7.

In otherwords, 2/3 in decimal places from 10 to 1 is:
0.6666666667
0.666666667
0.66666667
0.6666667
0.666667
0.66667
0.6667
0.667
0.67
0.7

However, with 0.99999999999999..... etc, it would be:
1.000000000
1.00000000
1.0000000
1.000000
1.00000
1.0000
1.000
1.00
1.0

Why?

If you round 0.647238 to 5 decimal places, the 8/1000000 rounds up to 10/1000000 which is equal to 1/100000 which adds on to the 3/100000 to make 4/100000 and therefore, it's 0.64724 to 5 decimal places.

Again, to 2 decimal places, the 7/1000 rounds up to 10/1000 which is 1/100 which adds on to the 4/100 to make 5/100 so the decimal to 2 places is 0.65

But how does it work for 0.999999........ well I just told you... but I'll say it again.
Let's just write it as 0.999999
If you continue to write it, the next number would be 9, but we're rounding it to 6 places, so that 9/10000000 rounds up to 10/10000000 which is 1/1000000 which adds on to the 9/1000000 which makes that 10/1000000 which is 1/100000 which adds on to the 9/100000 to make 10/100000 which is 1/10000 which adds onto the 9/10000 which makes that 10/10000 which is 1/1000 which adds onto the 9/1000 which makes that 10/1000, which is 1/100, plus the 9/100 = 10/100, which is 1/10, added onto the 9/10 makes 10/10 which is 1.
Click to expand...
But under that logic, wouldn't something like 0.25 = 0.256? Or 0.5 = 0.51?
Why are we rounding? How can we round infinite decimals?
What the hell are these mathematicians thinking?
Click to expand...

No you derp! You can round a number like 0.51 to 0.5, but you can't "unround" 0.5 to 0.51. 0.5 = 0.50 not 0.51

When you ROUND a number to a certain number of decimal places, even if the decimal is infinite, if the NEXT number is 5 - 9, the last number rounds up.

0.247
The 7 is between 5 and 9, so the 4 rounds up to 5 to make 0.25 to 2 decimal places

0.283, the 3 is NOT between 5 and 9 so the 8 does NOT round up, and it remains 0.28 to 2 decimal places

0.4999, the last 9 is between 5 and 9 so the previous 9 rounds up to '10', which means the 1 has to carry over to the PREVIOUS 9 and so it just goes to 0.5

Yes, 0.4999999999999999999999999999999................... = 0.5

Also, you want some even more simple proof that 0.999999999999........ = 1?

ALGEBRA TIME! WOOT!

Let x = 0.999999999999999999.........

When you multiply by 10, the decimal place basically moves one place to the right.
Therefore:
10x = 9.9999999999999999999.......

10x - x = 9x, i.e.:
9.9999999999999999...
-0.9999999999999999...
=9.0000000000000000...

Therefore, 9x = 9.000000000000000..., i.e. 9x = 9
Therefore x = 1
HA!
x = 0.9999999999999..., x = 1, therefore, 0.999999999999999.... = 1

Does it work with 0.499999999999999? Let's try.
x = 0.4999999...
10x = 4.999999...
9x = 10x - x, which is:
4.999999...
-0.499999...
=4.500000.... = 4.5
9x = 4.5
x = 0.5
Thus 0.4999999999............. = 0.5

YAY! My name is Sir Albert Gerald Brugh!! Or Albert G. Brugh. If you're really lazy, just call my Sir Al G Brugh.
 
Last edited by a moderator:
Hey.

Hey, guess what.

.9 repeating does not equal 1. Infinity is a concept, not a number, and cannot be rounded and calculated like real numbers.
 
Zexis said:
Hey.

Hey, guess what.

.9 repeating does not equal 1. Infinity is a concept, not a number, and cannot be rounded and calculated like real numbers.
Click to expand...
Exactly! That's what my maths teacher said a year back. Infinity is a concept, not a number. For example, .9 (repeating) really just means it's a .9 that goes on forever. Uncalculable.


As Zexis said, you can't calculate an "infinite" number. It can't happen. Especially since we don't have an actual utterly full understanding of the concept.
 
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